86.8k views
2 votes
Can you check my work please :)

I picked two coordinates, (5,1) and (0,-3) and i plugged them into the slope formula.

Y2-Y1/X2-X1

(5,1) 5 = X1 and 1 is = Y1

(0,-3) 0 =X2 and -3 is =Y2

When i plugged in the values, i got

-4/-5 = 0.8

slope is 0.8.

Tbh it looks wrong but I don't know.

Can you check my work please :) I picked two coordinates, (5,1) and (0,-3) and i plugged-example-1
User Gigoland
by
5.3k points

2 Answers

1 vote


\bf (\stackrel{x_1}{5}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{-2}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-2-1}{0-5}\implies \cfrac{-3}{-5}\implies \cfrac{3}{5}

User Jamshid
by
5.4k points
2 votes

Answer:

Your calculation is correct.The slope is indeed coming as 0.8

User Dimohamdy
by
4.7k points
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