Question

Find the vertex of the parabola. y= -4x^2+24x-35

Answer ASAP

Answer 1

vertex = (3, 1 )

Explanation:

Given a parabola in standard form : ax² + bx + c : a ≠ 0

The x- coordinate of the vertex is

`x_(vertex)` = -
`(b)/(2a)`

y = - 4x² + 24x - 35 ← is in standard form

with a = - 4 and b = 24, thus

`x_(vertex)` = -
`(24)/(-8)` = 3

Substitute x = 3 into the equation for corresponding value of y

y = - 4(3)² + 24(3) - 35 = - 36 + 72 - 35 = 1

Vertex = (3, 1 )

Answer 2

(3,1)

Explanation:

y=-4x^2+24x-35

x-intercept of the vertex formula:

v=-b/2a

a=-4

b=24,

c=-35

v = - 24/2(-4)

v = -24/-8

v = 3

substitute x as v

y= -4(3)^2 + 24(3) - 35

y= -4(9) + 72 - 35

y = -36 +72 - 35

y = 36 - 35

y = 1

therefore the vertex is

(3,1)