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Solve -3x^2-18x-35=0

User Haraman
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1 Answer

1 vote

Use the quadratic equation to solve this

Remember that quadratic functions are set up like so:


ax^(2) +bx +c = 0

That means that in this equation...

a = -3

b = -18

c = -35

^^^Plug these numbers into the quadratic equation and solve...


\frac{18+/-\sqrt{(-18)^(2)-4(-3)(-35)}}{2(-3)}


(18 +/-√(324+(-420)))/(-6)


(18+/-√(-96) )/(-6)


(18+/4i√(6) )/(-6)


(-9+/-2i√(6) )/(3)

Keep in mind that +/- is ±


(-9+2i√(6) )/(3)


(-9-2i√(6) )/(3)

^^^Exact answers

Hope this helped!

~Just a girl in love with Shawn Mendes

User Gomez NL
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