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This homework will be due when you come to lab. Two students are pushing identical crates across a frictionless floor. The crates are initially at rest. Bing applies a horizontal force of 23 N to his crate. Bob, who is shorter than Bing, pushes on his crate at an angle of 33° below the horizontal, also with a force of 23 N. Find the ratio of the masses of the two crates if Bing’s crate is moving at twice the speed of Bob’s crate after they have traveled a distance of 33.5 m

User Kevmar
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1 Answer

5 votes

Answer:

0.459

Step-by-step explanation:

Energy

1.
E = (1)/(2) mv^(2)

2.
E = Fx

Combining 1 and 2:

3.
m = (2Fx)/(v^(2) )

Using 3 to form the ratio:


(m_1)/(m_2) = (F_1)/(F_2) (v_2^(2) )/(v_1^(2) )

Given in the question:


v_1 = 2v_2


F_2 = F_1 sin(33)

Result:


(m_1)/(m_2) = (1)/(4sin(33))

User Usman Rana
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