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(20 pts!) if the base of the roof has length 40 feet and x=30, which of the following gives the height of the roof?

(20 pts!) if the base of the roof has length 40 feet and x=30, which of the following-example-1
User Phil John
by
8.1k points

2 Answers

5 votes

Answer:

40/√3 feet

Explanation:

Given,

Base of the roof,b=40 feet

Base angle,x=30°

Formula to calculate length of the roof,l=


(b)/( \cos(x) )

or,l=40/cos(30°)

or,l=40*(√3/2)

or,l=80/√3

Now,In the above triangle, using Pythagoras formula,

hypotenuse^2=base^2+height^2

If total height be h,

h^2+b^2=l^2

or,h^2=l^2-b^2

or,h^2=(80/√3)^2-40^2

or,h^2=6400/3 - 1600

or,h^2=1600/3

or,h=40/√3

ANS:40/√3 feet

User Joseluis
by
8.1k points
3 votes

Answer:

23.094 ft approximately

(If you want your answer in a different format, let me know please.)

Explanation:

I would have solve this using tangent since the side opposite to x is asked for and the adjacent side to side is given as having a measurement of 40 ft.

But I think they want you to use the formula:


l=(b)/(\cos(x)).


l=(40)/(\cos(30))

Input into calculator:


l=46.188 (approximation)

l represents the length of the roof.

So we have l=46.188 and b=40.

We must use the Pythagorean Theorem to find the height,h, for of the roof.

l is the hypotenuse.


h^2+40^2=46.188^2


h^2+1600=2133.331

Subtract 1600 on both sides:


h^2=533.331

Take square root of both sides:


h=23.094

The answer is 23.094 feet for the height that roof reaches on the building.

I want to show you another way:


\tan(x)=\frac{\text{opposite}}{\text{adjacent}}


\tan(30)=(h)/(40)

Multiply both sides by 40:


40\tan(30)=h

Input into calculator:


23.094=h

I didn't do it this way because your problem suggested you use their formula to find the height.

User Honchar Denys
by
8.2k points

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