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Approximately how far will an object fall in 5 ​sec, when thrown downward at an initial velocity of 20 ​m/sec from a​ plane?

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Apply this kinematics equation for the object's vertical motion:

D = Vt + 0.5At²

D = vertical distance traveled, t = time, V = initial vertical velocity, A = vertical acceleration

Given values:

V = 20m/s

A = 9.81m/s²

t = 5s

Plug in and solve for D:

D = 20(5) + 4.905(5)²

D = 223m

User Hoagy Carmichael
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