A thin circular ring of radius “a” has a uniformly distributed charge Q. Determine the electric potential at a point P on the axis of the ring at a distance x from its center.

Question

asked Sep 9, 2020 186k views

1 Answer

RobertAKARobin · Answer 1 · 2020-09-15T14:34:39+0000

Answer:

$E=\frac{KQx}{(x^2+a^2)^{(3)/(2)}}$

Explanation:

Given that

Radius of ring=a

Distance of point P from center=x

Total charge=Q

We know that electric field is given by

$E=(KQcos\theta )/(r^3)$

Here electric field in two direction will be cancel out and only in one direction electric field will exits.

$cos\theta =(x)/(r)$

r^2=x^2+a^2

$E=\frac{KQx}{(x^2+a^2)^{(3)/(2)}}$