Answer:
The fourth one is correct.
Explanation:
To show the diagonals are congruent, calculate their lengths using the Distance Formula: d=(x2−x1)2+(y2−y1)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√.
Find the length of LN.
Substitute 0 for x1, 2 for y1, 0 for x2 and −2 for y2.
LN=(0−0)2+(−2−2)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√
=02+(−4)2‾‾‾‾‾‾‾‾‾‾√
=8‾√
Find the length of MO.
Substitute 2 for x1, 0 for y1, −2 for x2 and 0 for y2.
MO=(−2−2)2+(0−0)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√
=(−4)2+02‾‾‾‾‾‾‾‾‾‾√
=8‾√
Since LN=MO, by the definition of congruent line segments, LN=MO.
To show the diagonals are perpendicular, calculate their slopes using the Slope Formula: m=y2−y1x2−x1.
Find the slope of LN.
Substitute 0 for x1, 2 for y1, 0 for x2 and −2 for y2.
m1=−2−20−0=−40⇒m1 cannot be defined.
Find the slope of MO.
Substitute 2 for x1, 0 for y1, −2 for x2 and 0 for y2.
m2=0−0−2−2
=0−4
=0
The slope of LN cannot be defined, this means that LN is parallel to y-axis. The slope of MO is equal to 0, this means that MO is parallel to x-axis. x and y axis are perpendicular, therefore LN⊥MO.
The figure shows the same square L M N O on a Cartesian plane as in the beginning of the task. Diagonal L N is perpendicular to diagonal M O.
To show the diagonals bisect each other, calculate their midpoints using the Midpoint Formula: P(x1+x22,y1+y22).
Find the midpoint of LN.
Substitute 0 for x1, 2 for y1, 0 for x2 and −2 for y2.
P1(0+02,2+(−2)2)=(0, 0)
Find the midpoint of MO.
Substitute 2 for x1, 0 for y1, −2 for x2 and 0 for y2.
P2(2+(−2)2,0+02)=(0, 0)
Both midpoints are the same point on the coordinate plane. This means the two diagonals intersect at their midpoints, or bisect each other.
The figure shows the same square L M N O on a Cartesian plane as in the beginning of the task. The diagonals intersect at point P. Segments L P, P N, M P, and P O are congruent.
Therefore, the diagonals are congruent perpendicular bisectors of each other.