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Trucks in a delivery fleet travel a mean of 110 miles per day with a standard deviation of 38 miles per day. The mileage per day is distributed normally. Find the probability that a truck drives between 132 and 159 miles in a day.

User DavidH
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1 Answer

1 vote

Answer: 0.1824

Explanation:

Given : The mileage per day is distributed normally with

Mean :
\mu=110\text{ miles per day}

Standard deviation :
\sigma=38\text{ miles per day}

Let X be the random variable that represents the distance traveled by truck in one day .

Now, calculate the z-score :-


z=(x-\mu)/(\sigma)

For x= 132 miles per day.


z=(132-110)/(38)\approx0.58

For x= 159 miles per day.


z=(159-110)/(38)\approx1.29

Now by using standard normal distribution table, the probability that a truck drives between 132 and 159 miles in a day will be :-


P(132<x<159)=P(0.58<z<1.29)\\\\=P(z<1.29)-P(0.58)\\\\= 0.9014747-0.7190426=0.1824321\approx0.1824

Hence, the probability that a truck drives between 132 and 159 miles in a day =0.1824

User Fes
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