Question

The tire on a bicycle is filled with air to a gauge pressure of 744 kPa at 20◦C. What is the gauge pressure in the tire after a ride on a hot day when the tire air temperature is 65◦C? (Assume constant volume and a constant atmospheric pressure of 101.3 kPa.) Answer in units of kPa.

Answer 1

Answer:
`P_f\left ( gauge\right )=975.124-101.3=873.824 KPa`

Step-by-step explanation:

Given

`P_i=744 KPa`

Initial Absolute pressure=744+101.3=845.3KPa

`T_i=20 ^(\circ)C\approx 293 k`

`T_f=65^(\circ)C\approx 338 k`

Using ideal gas equation

PV=mRT

here P=absolute pressure

Temperature in kelvin

thus
`(845.3)/(293)=(P_f)/(338)`

`P_f=975.124KPa\left ( absolute\right )`

`P_f\left ( gauge\right )=975.124-101.3=873.824 KPa`