Question

William burns 5.1 g of peanuts beneath 1000 g of water, which increases in temperature from 28◦C to 47◦C. Assuming 50% efficiency, what is the food value of the peanut? Answer in units of cal

Answer 1

food value of the peanut is 38 000 cal

Step-by-step explanation:

Heat observed by water

`Q = m* C * \Delta T`

C is a constant.

For water, C = 1 c gm/ °C

So here Q = (1000) (1 ) (47-28)

Q = 19 000 cal

FOR 50% efficiency,

Total heat released by peanut is:

19,000 cal / 0.50 = 38 000 cal

So the food value of the peanut is 38 000 cal.