Question

The work function for a metal surface is 4.98 eV. What is the largest wavelength of light in nm that will produce photoelectrons from this surface? (Use 1 eV = 1.602 ✕ 10−19 J, e = 1.602 ✕ 10−19 C, c = 2.998 ✕ 108 m/s, and h = 6.626 ✕ 10−34 J · s = 4.136 ✕ 10−15 eV · s as necessary.)

Answer 1

Answer:
`\lambda =248.99 nm`

Step-by-step explanation:

Given

Work function
`\left ( \phi \right )=4.98\approx 1.602* 10^(-19)* 4.98`

`h=6.626* 10^(-34) J`

`c=2.998* 10^8`

`\phi =(hc)/(\lambda )`

`\lambda =(hc)/(\phi )`

`\lambda =(6.626* 10^(-34)* 2.998* 10^8)/(4.98* 1.602* 10^(-19))`

`\lambda =248.99 nm`