Answer:
Explanation:
Given that a new restaurant with 138 seats is being planned. Studies show that 59% of the customers demand a smoke-free area.
Non smoke area = 100-59=41%
mu for non smoke area = 0.41
Std deviation =

mu-3sigma =

mu+3 sigma =

Thus 28.43 to 53.54 percent should be in non smoke area
Or 39.2334 to 73.8852 seats
74 seats should be in the non-smoking area in order to be very sure (mu plus 3 sigma) of having enough seating there