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The planetary model of the hydrogen atom consists of an electron in a circular orbit about a proton. The motion of the electron of charge 1.60 × 10−19 C creates an electric current. The radius of the electron orbit is 5.30 × 10−11 m and the electron's velocity is 2.20 × 106 m/s. What is the magnetic field strength at the location of the proton?

User AceCorban
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Final answer:

In the planetary model of the hydrogen atom, the electron's motion creates an electric current, which produces a magnetic field. By using the formula for the magnetic field produced by a current-carrying wire, we can calculate the magnetic field strength at the location of the proton. The magnetic field strength can be determined using the equation B = μ₀I/(2πr), where B is the magnetic field strength, μ₀ is the permeability of free space, I is the current, and r is the distance from the current-carrying wire.

Step-by-step explanation:

In the planetary model of the hydrogen atom, the electron orbits the proton in a circular path, similar to how planets orbit the sun. The motion of the electron creates an electric current, which in turn produces a magnetic field. To calculate the magnetic field strength at the location of the proton, we can use the formula for the magnetic field produced by a current-carrying wire. The magnetic field strength can be determined using the equation B = μ₀I/(2πr), where B is the magnetic field strength, μ₀ is the permeability of free space (4π × 10⁻⁷ Tm/A), I is the current, and r is the distance from the current-carrying wire.

Given that the radius of the electron orbit is 5.30 × 10⁻¹¹ m and the electron's velocity is 2.20 × 10⁶ m/s, we can calculate the current using the formula I = Q/t, where Q is the charge (1.60 × 10⁻¹⁹ C) and t is the time period for one complete revolution (T = 2πr/v), which can be determined by dividing the circumference of the orbit by the electron's velocity. Substituting the values into the equation, we find the current to be approximately 3.02 × 10⁻⁷ A.

Finally, substituting the current and radius values into the magnetic field formula, we can calculate the magnetic field strength at the location of the proton to be approximately 1.51 × 10⁻⁷ T.

User Juffy
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Answer:B=12.52 T

Step-by-step explanation:

Given


r=5.30* 10^(-11) m


v=2.2* 10^(6) m/s


q=1.60* 10^(-19) c


Magnetic field(B)=(\\u _0I)/(2r)


B=(\mu _0Q)/(2r* (2\pi r)/(v))


B=(4\pi * 10^(-7)* 1.6* 10^(-19))/(2* 5.30* 10^(-11)* 15.138* 10^(-17))

B=12.52 T

User Karishma Malkan
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