Question

A garden hose with an internal diameter of 2.5 cm is connected to a (stationary) lawn sprinkler that consists merely of a container with 28 holes, each 0.20 cm in diameter. If the water in the hose has a speed of 0.85 m/s, at what speed does it leave the sprinkler holes?

Answer 1

4.7433 m/sec

Explanation:

Given data

the internal diameter of garden =2.5 cm =0.025 m

radius
`r_1`= 0.0125 m

it contains 28 holes each of diameter 0.20 cm =0.002 m

radius
`r_2` =0.001 m

from continuity equation

`A_1V_1=nA_2V_2`

where A is area and V is velocity

0.85×
`A_1`=28 ×
`A_2`×
`V_2`

`V_2=(A_1)/(28A_2)* V_1=(r_1^2)/(28r_2^2)* 0.85=4.7433 m/sec`