Answer:
Explanation:
p1(-3,2) p2(2,6)
find the slope of the line between these two points
m= 6-2 /2-(-3)
m=4/5
find the slope of the line between p2 and p3(8,-1)
m=-1-6 /8-2
m=-7 / 6
dist= sqrt( (8-(-3))^2+(-1-2)^2)
dist = 11.40175 (1 to 3) hyp
dist = sqrt( (8-2)^2 + (-1-6)^2)
dist = 9.219544 (2 to 3)
dist = sqrt( (2-(-3))^2 + (6-2)^2)
dist = 6.403124 ( 1 to 2)
use law of cosines to find an angle
law of cosines cos(C) = (a^2+b^2-c^2) / (2ab) =97.61°
cos(A) = (b^2+c^2-a^2) / ( 2bc) = 32.23°
cos(B) = (a^2+c^2-b^2) / (2ac) =50.16°
do the same process as above but for the points in 23
This took me a few hours :/ granted I took a break for dinner but still .. pay me for that much work :D.. if you can't get 23 later re post question I'll work on it later