Answer:
The initial speed of the ball is 3.93 m/s.
Step-by-step explanation:
It is given that,
A ball is thrown horizontally from a height of 19 m, h = 19 m
Let u is the initial speed of the ball so, its final velocity, v = 5u
Using third equation of motion as :
![v^2-u^2=2gh](https://img.qammunity.org/2020/formulas/engineering/college/irqm42pipuboh3oeb2jf3k5v9zi5gb3mmc.png)
![(5u)^2-u^2=2* 9.8* 19](https://img.qammunity.org/2020/formulas/physics/high-school/ecbal4r7nn8fwi3e6opt52kf04cgq11vnt.png)
![24u^2=372.4](https://img.qammunity.org/2020/formulas/physics/high-school/zq36as63pajsppwdpo2gphd3jv9n7xk3zi.png)
u = 3.93 m/s
So, the initial speed of the ball is 3.93 m/s. Hence, this is the required solution.