Answer with explanation:
Total number of cards in the deck =50
There are card numbered from 1 to 10 in 5 suits.
We have to calculate 5 card hands in the deck that include exactly one pair of two cards that have the same numeric value
![\rightarrow_(2)^(5)\textrm{C}=(5!)/((5-2)!2!)\\\\=(5!)/((3!)2!)\\\\=(3! * 4 * 5)/(3! * 2!)\\\\=(20)/(2)\\\\=10](https://img.qammunity.org/2020/formulas/mathematics/high-school/c74cl7ccd6kao9dy2tmmj37za0g7d3w2f2.png)
So, if you will find pairs in each card numbered from 1 to 10, there will be 10 distnct pairs if there are 5 suits of each card.