Question

The A string of a violin is a little too tightly stretched. Beats at 5 per second are heard when the string is sounded together with a tuning fork that is oscillating accurately at concert A (4.40 × 102 Hz). What is the period of the violin string oscillation?

Answer 1

2.232×10⁻³ seconds

Step-by-step explanation:

Number of beats with respect to time = 5 beats/s

F = String is oscillating at 4.4×10² Hz

A beat is a pattern of interference between two different frequencies.

`\text{Beat frequency}=(1)/(T)-F\\\Rightarrow 5=(1)/(T)-440\\\Rightarrow (1)/(T)=445\\\Rightarrow T=(1)/(445)\\\Rightarrow T=0.002247\ s`

Time periods is 2.247×10⁻³ seconds

Answer 2

Answer:T=
`2.27* 10^(-3)`

Step-by-step explanation:

Given the frequency of tuning fork be 440 HZ

let the frequency of Violin string be F

beat frequency =F-440 =5

therefore

F=445 Hz

Period of oscillation of string=
`(1)/(F)`

`T=2.27* 10^(-3) s`