Question

Determine the volume at the equivalence point if a 0.100 M NaOH(aq) solution is used to titrate the following acidic solutions: (a) 50.0 mL of 0.200 M HBr(aq) (b) 30.0 mL of 0.150 M HNO3(aq)

Answer 1

a) NaOH volume at the equivalence point is 100 ml.

b) NaOH volume at the equivalence point is 45 ml.

Step-by-step explanation:

To calculate the concentration of acid, we use the equation given y neutralization reaction:

`n_1M_1V_1=n_2M_2V_2`

where,

`n_1,M_1\text{ and }V_1` are the n-factor, molarity and volume of acid.

`n_2,M_2\text{ and }V_2` are the n-factor, molarity and volume of base

a) If a 0.100 M NaOH (aq) solution is used to titrated with 50.0 mL of 0.200 M HBr(aq).

We are given:

`n_1=1\\M_1=0.200M\\V_1=50.0mL\\n_2=1\\M_2=0.100M\\V_2=?mL`

Putting values in above equation, we get:

`1* 0.200M* 50.0 mL=1* 0.100 M* V_2\\\\V_2=100 mL`

b) If a 0.100 M NaOH (aq) solution is used to titrated with 30.0 mL of 0.150 M
`HNO_3`(aq).

We are given:

`n_1=1\\M_1=0.150M\\V_1=30.0mL\\n_2=1\\M_2=0.100M\\V_2=?mL`

Putting values in above equation, we get:

`1* 0.150M* 30.0 mL=1* 0.100 M* V_2\\\\V_2=45 mL`