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Soap bubbles can display impressive colors, which are the result of the enhanced reflection of light of particular wavelengths from the bubbles' walls. For a soap solution with an index of refraction of 1.27, find the minimum wall thickness that will enhance the reflection of light of wavelength 715 nm in air.

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Answer:

T= 563/4= 140.75 nm

Step-by-step explanation:

Soap bubbles can display impressive colors.

In a bubble there are two surfaces the first surface has a phase shift of 180° and second surface has 0° phase shift.

so total
\pi

wavelength λ= 2π

hence wavelength λ/2

Also λ=
(715)/(1.27)

= 562.9921≅563 nm

also wall thickness T


2T= (λ)/(2)

T= λ/4

⇒T= 563/4= 140.75 nm

User Thai Ha
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