Question

One wire carries a current of I1= 2 Amps, and the other carries a parallel current (same direction, wires are side by side) of I2=0.75 Amps. They are 5 meters long in this configuration and separated from each other by 5 cm. What is the magnitude of the force experienced by the wire carried I2?

Answer 1

Answer:
`F=3* 10^(-5) N`

Step-by-step explanation:

Given

`I_1=2 Amps`

`I_2=0.75 Amps`

Length of each wires
`\left ( L\right )=5 m`

Distance between wires
`\left ( r\right )=5 cm`

Force per unit length =
`(\mu_0I_1I_2)/(2\pi r)`

`F'=(2* 10^(-7)* 2* 0.75)/(2\pi * 0.05)`

`F'=6* 10^(-6)`

Force for
`L=5 m`

`F=3* 10^(-5) N`