Answer:
P(heads on first time ) =
![(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/g8uu853hd4xgpf51yzryheaugm47qujkf6.png)
P(tails on last flip) =
![(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/g8uu853hd4xgpf51yzryheaugm47qujkf6.png)
Explanation:
when Percival flips coin several times and record the result.
so every time he tosses coin there is probability of getting heads or tails is
P(heads) =
![(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/g8uu853hd4xgpf51yzryheaugm47qujkf6.png)
and for tails
P(tails) =
![(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/g8uu853hd4xgpf51yzryheaugm47qujkf6.png)
so, probability of getting heads while tossing coin first time is equal to
P(heads on first time ) =
![(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/g8uu853hd4xgpf51yzryheaugm47qujkf6.png)
again, probability of getting tails while tossing coin for last time is equal to
P(tails on last flip) =
![(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/g8uu853hd4xgpf51yzryheaugm47qujkf6.png)