Question

A cylinder contains a mixture of helium and argon gas in equilibrium at a temperature of 233◦ C. The value of Boltzmann’s constant is 1.38066 × 10−23 J/K, and Avogadro’s number is 6.02 × 1023 mol−1. What is the average kinetic energy of each type of molecule? Answer in units of J.

Answer 1

Answer : The average kinetic energy is,
`1.04742* 10^(-20)J`

Explanation :

The formula for average kinetic energy is:

`K.E=(3)/(2)kT`

where,

k = Boltzmann’s constant =
`1.38066* 10^(-23)J/K`

T = temperature =
`233^oC=273+233=506K`

Now put all the given values in the above average kinetic energy formula, we get:

`K.E=(3)/(2)* (1.38* 10^(-23)J/K)* (506K)`

`K.E=1.04742* 10^(-20)J`

Therefore, the average kinetic energy is,
`1.04742* 10^(-20)J`