Question

Find the speed of light in each of the following materials. (a) gallium phosphide m/s (b) carbon disulfide m/s (c) benzene

Answer 1

Step-by-step explanation:

We need to calculate the speed of light in each materials

(I). Gallium phosphide,

The index of refraction of Gallium phosphide is 3.50

Using formula of speed of light

`v=(c)/(\mu)`....(I)

Where,
`\mu` = index of refraction

c = speed of light

Put the value into the formula

`v=(3*10^(8))/(3.50)`

`v=8.6*10^(7)\ m/s`

(II) Carbon disulfide,

The index of refraction of Gallium phosphide is 1.63

Put the value in the equation (I)

`v=(3*10^(8))/(1.63)`

`v=1.8*10^(8)\ m/s`

(III). Benzene,

The index of refraction of Gallium phosphide is 1.50

Put the value in the equation (I)

`v=(3*10^(8))/(1.50)`

`v=2*10^(8)\ m/s`

Hence, This is the required solution.