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As we've seen, astronauts measure their mass by measuring the period of oscillation when sitting in a chair connected to a spring. The Body Mass Measurement Device on Skylab, a 1970s space station, had a spring constant of 606 N/m. The empty chair oscillated with a period of 0.848 s.What is the mass of an astronaut who oscillates with a period of 2.26 s when sitting in the chair?

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Answer:

mass of astronaut is M 67.362 kg

Step-by-step explanation:

Given details:

spring constant k = 606 N/m

Time T = 0.848 s

The time period is


T = (2\pi)\sqrt{(m)/(k)}

So the mass of the empty chair is


m = [(T)/(2\pi)]^2 k


= [(0.848)/(2\pi)]^2*606

= 11.038 kg

When astronaut is sitting in the chair then the time period is


T' = (2\pi)\sqrt{(m')/(k)}


m' = [(T')/(2\pi)]^2k


=[(2.26)/(2\pi)]^2*606

m' = 78.40 kg

mass of astronaut is M = m' - m

= (78.40 kg) - ( 11.038 kg)

= 67.362 kg

User Bruno Berisso
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