Question

A single conducting loop of wire has an area of 8.0×10−2 m2 and a resistance of 110 Ω . Perpendicular to the plane of the loop is a magnetic field of strength 0.40 T .

Part A
At what rate (in T/s) must this field change if the induced current in the loop is to be 0.26 A ? Express your answer using two significant figures.

Answer 1

Step-by-step explanation:

It is given that,

Area of the loop,
`A=8* 10^(-2)\ m^2`

Resistance,
`R=110\ \Omega`

Induced current, I = 0.26 A

We know that emf is given by :

`E=A.(dB)/(dt)`

From Ohm's law, E = IR

`IR=A.(dB)/(dt)`

`(dB)/(dt)=(IR)/(A)`

`(dB)/(dt)=(0.26\ A* 110\ \Omega)/(8* 10^(-2)\ m^2)`

`(dB)/(dt)=357.5\ T/s`

So, field is changing at the rate of 357.5 T/s. Hence, this is the required solution.