Answer:
A consumer organization estimates that over a 1-year period 16% of cars will need to be repaired once, 9% will need repairs twice, and 3% will require three or more repairs..
We have the cars that do not need repair =
%
(16+9+3=28% cars need repair of some sort)
What is the probability that :
a) neither will need repair?
=>
![0.72*0.72=0.5184](https://img.qammunity.org/2020/formulas/mathematics/high-school/j1lnsp253xbmbb2rpjjkjizig7gdoouj1g.png)
b) both will need repair?
=>
c) at least one car will need repair?
=>
![1-(0.72*0.72)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ouejrp9e2ki756k9mwi2ryde8zts5wispd.png)
=>
![1-0.5184=0.4816](https://img.qammunity.org/2020/formulas/mathematics/high-school/niqfci48d1zdfjjk301230psgw6socm7bo.png)