163k views
1 vote
In a certain physics experiment, carts run along a frictionless, level track. Cart A is 1 kg and Cart B is 2 kg. Initially cart A is moving to the right at 3.0 m/s and cart B is moving to the left at 7.0 m/s. After they collide, they stick together. What is the magnitude of the velocity of the two carts?

User DrC
by
6.7k points

1 Answer

6 votes

Answer:
v=-(11)/(3) m/s \left

Step-by-step explanation:

Given

Mass of car A
\left ( m_a\right )=1 kg

Mass of car B
\left ( m_b\right )=2 kg

velocity of cart A=3 m/s

velocity of cart B=-7 m/s

Conserving momentum


m_au_a+m_bu_b=\left ( m_a+m_b\right )v


v=(m_au_a+m_bu_b)/(\left ( m_a+m_b\right ))


v=-(11)/(3) m/s \left ( i.e. in\ left\right )

User Uooq
by
6.5k points