Question

Angelo invested

$4,000
into two accounts. One account paid
4%
interest and the other paid
9%
interest. He earned
6%
interest on the total investment. How much money did he put in each account?

Answer 1

The amount invested in account that paid 4% was $2,400

The amount invested in account that paid 9% was $1.600

Explanation:

Let

x -----> amount invested in account that paid 4%

(4,000-x) -----> amount invested in account that paid 9%

we know that

The linear equation that represent this scenario is

`x(0.04)+(4,000-x)(0.09)=4,000(0.06)`

Solve for x

`0.04x+360-0.09x=240`

`0.09x-0.04x=360-240`

`0.05x=120`

`x=\$2,400`

`(4,000-x)=4,000-2,400=\$1,600`

therefore

The amount invested in account that paid 4% was $2,400

The amount invested in account that paid 9% was $1.600