Answer:
3.04 seconds
Explanation:
Two identical rubber balls are dropped from different heights. Ball 1 is dropped from a height of 148 ft, and ball 2 is dropped from a height of 203 feet. Using the function f(t) = -16t^2+h to determine the current height, f(t), a ball is dropped from a height h, over a given time t, ball 1 reaches the ground in 3.04 seconds.