Answer:
The momentum of the system, bullet and rifle just after the bullet leaves the barrel is zero, 3.6 kg m/s and -3.6 kgm/s respectively
Step-by-step explanation:
Given that,
Mass of the rifle = 6 kg
Mass of the bullet = 12 g
Velocity of bullet = 300 m/s
We need to calculate the momentum of bullet
Using formula of momentum
Where, m = mass of bullet
v = velocity of bullet
Put the value into the formula
The momentum of the bullet is 3.6 kgm/s.
The momentum of rifle is opposite direction of momentum of bullet and equal in magnitude.
The momentum of rifle = - 3.6 kgm/s
Therefore, The momentum of system must be zero.
Hence, The momentum of the system, bullet and rifle just after the bullet leaves the barrel is zero, 3.6 kg m/s and -3.6 kgm/s respectively.