183k views
1 vote
Randomly selected students participated in an experiment to test their ability to determine when one minute​ (or sixty​ seconds) has passed. Forty students yielded a sample mean of 59.8 seconds. Assuming that sigmaequals9.2 ​seconds, construct and interpret a 90​% confidence interval estimate of the population mean of all students.

User Zmechanic
by
4.4k points

1 Answer

5 votes

Answer:
(57.41,\ 62.19)

Explanation:

Given : Sample size :
n=40

Sample mean :
\overline{x}=59.8\text{ seconds}

Standard deviation :
\sigma =9.2\text{ seconds}

Significance level :
\alpha=1-0.9=0.1

Critical value :
z_(\alpha/2)=1.645

Formula to find the confidence interval for population mean :-


\overline{x}\pm z_(\alpha/2)(\sigma)/(√(n))\\\\=59.8\pm(1.645)(9.2)/(√(40))\\\\\approx59.8\pm2.39\\\\=(59.8-2.39,\ 59.8+2.39)\\\\=(57.41,\ 62.19)

Hence, a 90​% confidence interval estimate of the population mean of all students =
(57.41,\ 62.19)

User Josh Heitzman
by
4.8k points