Question

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the

correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag
the item to the trashcan. Click the trashcan to clear all your answers.
Input the equation of the given line in standard form.
The line including (3, 1) and (-2, 3).

Answer 1

10x + 5y = 11

Explanation:

I usually find it in slope intercept then convert, it's easier for me.

First you find slope using delta y over delta x giving you -2/5.

so you have y=-2/5x + b

To find b plug in a point and solve down

1 = -2/5(3) +b

1+6/5 = b

b = 11/5

y=-2/5x + 11/5

Then you convert it to Ax+by=C form,

multiply by 5

5y = -10x + 11

move x

10x +5y = 11

Answer 2

`2x+5y-11 =0`

Explanation:

Givens

Coordinates
`(3,1)` and
`(-2,3)`

We need to find the equation of the line that passes through those points.

First, we have to find its slope with the following formula

`m=(y_(2)-y_(1) )/(x_(2) -x_(1) )`

We replace the given points

`m=(3-1)/(-2-3)=(2)/(-5)`

Now, we use the point-slope formula to find the equation

`y-y_(1) =m(x-x_(1) )\\y-1=-(2)/(5)(x-3)\\ y-1=-(2)/(5)x +(6)/(5)\\ y+(2)/(5)x-(6)/(5)-1=0\\(2)/(5)x+y-(11)/(5) =0`

But, the standard form is
`Ax+By+C=0`

So, if we multiply the equation by 5, we would have a better representation

`2x+5y-11 =0`