Answer:
Option D is correct answer.
Explanation:
We are given the system of equations:
![x+y=4\\x-y=-6](https://img.qammunity.org/2022/formulas/mathematics/high-school/s7llhao248c8xqfigew35rgsivyrs1jjmj.png)
Solving the system of equations to find values of x and y
Let:
![x+y=4--eq(1)\\x-y=-6--eq(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/rltgki8myfzaim271jfy4poamyilsav94z.png)
Adding both equations to find value of x
![x+y=4\\x-y=-6\\------\\2x=-2\\x=(-2)/(2)\\x=-1](https://img.qammunity.org/2022/formulas/mathematics/high-school/ern50brazjhgpmoxpwq79j21hburi33frr.png)
So, we get value of x: x=-1
Now, putting value of x: x=-1 into equation 1 to find value of y
![x+y=4\\Putx=-1\\-1+y=4\\y=4+1\\y=5](https://img.qammunity.org/2022/formulas/mathematics/high-school/82qwh9i4qqhmmudlrtk4w3wxwu2g61pc7r.png)
So, we get value of y: y=5
The ordered pair will be: (-1,5)
So, Option D: The ordered pair(-1,5) is a a solution to the system of equations because it makes both equations true is correct choice.
Checking:
Put x=-1 and y=5 in equation 1
![x+y=4\\-1+5=4\\4=4\:True](https://img.qammunity.org/2022/formulas/mathematics/high-school/870mubpwtkgd6b4fxg9ap1a2heo0bs4xdy.png)
Put x=-1 and y=5 in equation 2
![x-y=-6-1-5=-6\\-6=-6\:\:\:True](https://img.qammunity.org/2022/formulas/mathematics/high-school/jt3j53sjrzyrezq0hol1hjegv6xn6cq694.png)
So, both equations are true.
Therefore, Option D is correct answer.