Question

An AC power source has an rms voltage of 1.20x 102 V and operates at a frequency of 60.0 Hz. If a purely inductive circuit is made from the power source and a 47.0 H inductor, determine the rms current in mA through the inductor.

Answer 1

8.127 mA

Step-by-step explanation:

We have given RMS value of AC voltage =1.2×120=144 V

frequency=60 Hz

inductance = 47 Hz

Inductive reactance
`X_L=2* \pi * f* L`

`X_L=2* \pi * 60* 47=17718.5825\ ohm`

current
`I=(V)/(X_L)=(144)/(17718.5825)=0.008127\ A=8.127\ mA`

So the inductor current will be 8.127 mA