Question

Can someone help answer this question Ive tried a lot and couldnt do it.

Find the surface area of each figure. Round the answer to two decimal places. (use π = 3.14) Do not include units of measure in your answer.
PIctrue down below

Answer 1

1222

Explanation:

You have a triangular prism on top of a rectangular prism. The surface area is the sum of the areas of the exposed faces.

Starting with the triangular prism, the surface area is the area of the two triangular bases plus the area of the two rectangular sides (the bottom rectangular face is ignored).

A = ½ (10) (12) + ½ (10) (12) + (13) (9) + (13) (9)

A = 60 + 60 + 117 + 117

A = 354

The surface area of the rectangular prism is the area of the two rectangular bases (front and back), plus the two walls (left and right), plus the bottom, plus the top (minus the intersection with the top prism).

A = (19) (11) + (19) (11) + (9) (11) + (9) (11) + (19) (9) + (19) (9) − (10) (9)

A = 209 + 209 + 99 + 99 + 171 + 171 − 90

A = 868

So the total surface area is:

354 + 868

1222

Answer 2

Total surface area=1222

Find the area of the triangular bases plus the area of the two rectangular sides (the bottom rectangular face is ignored).

Area of triangular base A = ½ (10) (12) + ½ (10) (12) + (13) (9) + (13) (9)

A = 60 + 60 + 117 + 117

A = 354

The total surface area of the rectangular prism encompasses the combined area of both rectangular bases (front and back), the areas of the two lateral walls (left and right), the bottom face, and the top face (excluding the overlapping region with the upper prism).

A = (19) (11) + (19) (11) + (9) (11) + (9) (11) + (19) (9) + (19) (9) − (10) (9)

A = 209 + 209 + 99 + 99 + 171 + 171 − 90

A = 868

So the total surface area is:

354 + 868

1222