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You have to heat up a 1.000 gram ingot of aluminum from initial temperature Ti = 847 K to its melting point, 933 K. Calculate the number of calories required for this heat up process. Type in the numeric part of your answer to the nearest 0.1 calorie. E.g., if your answer is 31.38 calories, than type 31.4 in the answer box.

1 Answer

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Answer: 18.9 calories

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.


Q=m* c* \Delta T

Q = Heat absorbed

m= mass of substance = 1.0 g = 0.001 kg

c = specific heat capacity of aluminium =
921.096J/kgK

Initial temperature =
T_i = 847 K

Final temperature =
T_f = 933 K

Change in temperature ,
\Delta T=T_f-T_i=(933-847)K=86K

Putting in the values, we get:


Q=0.001kg* 921.096J/kgK* 86K


Q=79.2J=18.9cal (1J=0.24cal)

The number of calories required for this heat up process is 18.9 calories.

User Zhubei Federer
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