Answer:
speed of water lower is 3.11 m/s
pressure at the upper level is 261660.95 Pa
Step-by-step explanation:
Given data
speed = 5.7 m/s
cross-sectional area =4.8 cm2
water gradually descends = 9.2 m
pipe increases = 8.8 cm2
to find out
speed at the lower level and pressure at the upper level
solution
we will apply here continuity equation i.e
area of pipe top × speed of water top = area of pipe lower × speed of water lower
so speed of water lower = area of pipe top × speed of water top / area of pipe lower
put all value
speed of water lower = 4.8 × 5.7 / 8.8
speed of water lower is 3.11 m/s
in 2nd part we apply bernoulli equation that is
P1 + 1/2 ρ v1² + ρgh1 = P2 + 1/2 ρ v2² + ρgh2
here we know h1 and h2 is initial and final height and ρ is water density
so we calculate p2 here i.e
p2 = P1 + 1/2 ρ (v1² - v2²) + ρg (h1-h2)
put all value we get p2
p2 = 1.6 × 10^5 + 1/2 (1000) (5.7² - 3.11²) + 1000(9.81) (9.2)
p2 = 261660.95 Pa
pressure at the upper level is 261660.95 Pa