Question

A straight wire in a magnetic field experiences a force of 0.030 N when the current in the wire is 2.7 A. The current in the wire is changed, and the wire experiences a force of 0.047 N as a result. What is the new current?

Answer 1

current is 4.23 A

Step-by-step explanation:

Given data

force f1 = 0.030 N

current I = 2.7 A

force f2 = 0.047 N

to find out

the new current

solution

we know that force = flux density(B) × current(I) × length(L) ...............1

f1 = BL × current

so BL = 0.030/ 2.7 = 0.011111

now put BL and f2 in equation 2 we get current

force = flux density(B) × current(I) × length(L)

0.047 = 0.01111 × current

current = 0.047 / 0.01111

current is 4.23 A