Question

I

A 10 kg box is pulled across the floor at a constant speed. If the force of pull was 70 N at
a 30° angle:
a. What was the force of friction
b. What was the coefficient of friction

Answer 1

Acceleration equals zero because of constant velocity

`f - fr = ma \\ 70 \cos(30) - fr = 0 \\ 70 \cos(30) = fr \\ fr \: = 60.62`

coefficient

Fr = coefficient × r

60.62= ce ×100

0.60 = coefficient