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How much heat is absorbed by 62g iron skillet when it's temperature rises from 8c to 27c

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Answer:

530 J

Step-by-step explanation:

Heat absorbed is:

q = mCΔT

where m is mass, C is the specific heat, and ΔT is the temperature increase.

The specific heat of iron is 0.449 J/g/C. Therefore:

q = (62 g) (0.449 J/g/C) (27°C − 8°C)

q ≈ 529 J

Rounded to two significant figures, the heat absorbed is approximately 530 J.

User Cancerian
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