Answer:
![(1)/(5525)](https://img.qammunity.org/2020/formulas/mathematics/high-school/893h41ppro6gqbhcsmcva7izu6t4aml85t.png)
Explanation:
The total number of cards =52
The number of kings in the cards = 4
If repetition is not allowed , then the total number of ways of choosing 3 cards will be :-
![52*51*50=132600](https://img.qammunity.org/2020/formulas/mathematics/high-school/mhmibc1lamsjve20763mkr1ir13868kmml.png)
The number of ways of choosing 3 kings will be :-
![4*3*2=24](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bpsxv2dhfb0ketzybjri8hnsqdedmfndzo.png)
Now, the probability of choosing 3 king cards will be :-
![(24)/(132600)=(1)/(5525)](https://img.qammunity.org/2020/formulas/mathematics/high-school/f23yhgudpzsq00l7dhret1f8k0lpnxzjt0.png)
Hence, the probability of choosing 3 king cards =
![(1)/(5525)](https://img.qammunity.org/2020/formulas/mathematics/high-school/893h41ppro6gqbhcsmcva7izu6t4aml85t.png)