Question

In rabbits, spotted coats (S) are dominant to solid colored coats (s), and short hair is (L) is dominant to long hair (l). A homozygous spotted, long haired male is mated to a fully solid-colored, homozygous shorthaired female rabbit. If the F1 offspring were allowed to interbreed and 64 offspring were produced, how many of the 64 would you predict would be spotted with long hair, and how many will be solid colored with short hair?

Answer 1

spotted with long hair - 0

solid colored with short hair - 0

Step-by-step explanation:

Given -

Spotted coats (S) are dominant to solid colored coats (s)

Short hair is (L) is dominant to long hair (l)

Genotype of homozygous spotted, long haired male is "SSll"

Genotype of fully solid-colored, homozygous short haired female rabbit is "ssLL"

Allele s for above two genotype are –

“SSll” – Sl, Sl, Sl, Sl

“ssLL” – sL, sL, sL, sL

The cross between "SSll" and "ssLL" is represented by a punnett square as shown below -

SSll" and "ssLL

Sl Sl Sl Sl

sL SsLl SsLl SsLl SsLl

sL SsLl SsLl SsLl SsLl

sL SsLl SsLl SsLl SsLl

sL SsLl SsLl SsLl SsLl

So all 16 type genotype are "SsLl" which depict heterozygous genotype for phenotype "Spotted coats and short hair"

So frequency of species with spotted with long hair is equal to zero

Frequency of species with solid colored with short hair is equal to zero