Question

A 97 kg man lying on a surface of negligible friction shoves a 62 g stone away from himself, giving it a speed of 2.6 m/s. What speed does the man acquire as a result?

Answer 1

man will move in opposite direction with speed

`v_1 = 1.66 * 10^(-3) m/s`

Step-by-step explanation:

As we know that man is lying on the friction-less surface

so here net force along the surface is zero

so if we take man + stone as a system then net change in momentum of this system will become zero

so here we have

`P_i = P_f`

`0 = m_1v_1 + m_2v_2`

here we have

`0 = (97)v_1 + 0.062(2.6)`

`v_1 = -(0.1612)/(97)`

`v_1 = -1.66 * 10^(-3) m/s`