Answer:
P (z for -2.23) is -0.9871
Explanation:
Given data
mean life x = 753 hours
sample n = 28
mean y = 726
standard deviation SD = 64 hours
to find out
check to have enough evidence to reject his claim
solution
we know that given mean is x ≥ 753
we found mean = 726
so difference = y - x = 726 - 753 = -27
and we know σ = SD/√n = 64 / √28 = 12.094896
Z = y - x / σ
Z = -27 / 12.09
Z = -2.23
so probability value
P (z for -2.23) is -0.9871
so z value is less than alpha = 0.05
so reject
so this is enough evidence to reject his claim