Question

A coaxial cable consists of an inner conductor with radius ri = 0.20 cm and an outer radius of ro = 0.4 cm and has a length of 13 meters. Plastic, with a resistivity of ρ = 2.00 ✕ 1013 Ω · m, separates the two conductors. What is the resistance (in Ω) of the plastic when current is flowing between the two conductors of the coaxial cable?

Answer 1

`R = 1.69*10^(11) ohm`

Step-by-step explanation:

ri = 0.20cm

ro = 0.4 cm

length L = 13m

resistivity \rho = 2.00*10^13 ohm m

resistance can be determine by using following relation

`R = (\rho)/(2\pi L) ln(ro)/(ri)`

`R = (2.00*10^(13))/(2\pi *10) ln(.004)/(.002)`

`R = 1.69*10^(11) ohm`