Question

Ms. Johnson uses a statistics program to analyze all the data collected by her students during a lab experiment about acceleration due to gravity. The program reports a mean of 31.5 and a standard deviation of 2.5. What is the variance of the data? Round to the nearest tenth. a. 2.5b. 5.6c. 1.6d. 6.3

Answer 1

Answer: 6.3

Step-by-step explanation: sigma^2 (2.5^2) equals 2.5x2.5 = 6.3, so it would be 6.3.

Answer 2

Answer: d. 6.3

Explanation:

Given : Ms. Johnson uses a statistics program to analyze all the data collected by her students during a lab experiment about acceleration due to gravity.

The program reports a mean
`\mu=31.5` and a standard deviation
`\sigma=2.5`

We know that the variance is the square of the standard deviation.

So , the variance of the data will be :-

`\text{Variance}=\sigma^2=(2.5)^2=6.25\approx6.3`

Hence, the variance of the data =6.3