Answer:
94.05 mV
Explanation:
N = Number of turns = 149
r = Radius of coil = 2.45 cm = 0.0245 m
t = Time = 0.141 s
Initial magnetic field = 50.9 mT
Final magnetic field = 98.1 mT
A = Area = πr² = π×0.0245²
![\text{Induced emf}=NA(dB)/(dt)\\\Rightarrow \text{Induced emf}=149* \pi * 0.0245^2((98.1-50.9)* 10^(-3))/(0.141)\\\Rightarrow \text{Induced emf}=0.09405 V = 94.05 mV](https://img.qammunity.org/2020/formulas/mathematics/college/g83ka72ei06p724o6n5yfa8frometr9k63.png)
∴ Magnitude of the average EMF, that is induced in the coil during this time interval is 94.05 mV