Question

If a single die is rolled four ​times, what is the probability it lands on 4 on the first comma second and third nothingnothing​rolls, but not on any of the other​ rolls?

Answer 1

probability comes out to be
`(5)/(1296)`

Explanation:

when the dice is singly rolled

chances of getting 4 (Y)is
`(1)/(6)`

and,

chance of not getting 4 (N) is
`(5)/(6)`

probability of getting 4 on first, second and third time and not on the forth time is

P( Y, Y, Y, N ) =
`(1)/(6) * (1)/(6) * (1)/(6) * (5)/(6)`

=
`(5)/(1296)`

so the probability comes out to be
`(5)/(1296)`